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翻译 北美求职 每天59秒拿下每日一题 转码 程序员 RedNote 国区每日一题今日思路(.cn)： 优先队列。操作数不会超过数组长度，使用优先队列维护小根堆，每次将最小两个元素出队进行操作，直到堆顶元素不小于k。 Priority Queue: The number of operations will not exceed the length of the array. Use a priority queue to maintain a min-heap. Each time, dequeue the two smallest elements for processing until the top element of the heap is no less than k. 国际站每日一题今日思路(.com)： 贪心。记a和b分别为num1和num2的有效置位。优先将有效置位放置在与num1高位相同的位置，这样异或运算结果最小。若有剩余从低位向高位找非有效置位填1。 Greedy Algorithm: Given a and b represent the significant set bits of num1 and num2 respectively. Prioritize placing the significant set bits in positions that align with the higher-order bits of num1. If there are remaining bits, fill them by setting non-significant bits to 1 from the lower to higher positions. 看到这点个赞吧[喝奶茶R] Give me a link and a follow if you found it helpful!